1805 Georgia gubernatorial election
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Elections in Georgia |
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The 1805 Georgia gubernatorial election was held on 4 November 1805 in order to elect the governor of Georgia. Incumbent Democratic-Republican governor John Milledge won re-election in a Georgia General Assembly vote as he ran unopposed.[1]
General election
[edit]On election day, 4 November 1805, incumbent Democratic-Republican governor John Milledge won re-election as he ran unopposed. Milledge was sworn in for his second full term on 4 November 1805.[2]
Results
[edit]Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic-Republican | John Milledge (incumbent) | 61 | 100.00 | |
Total votes | 61 | 100.00 | ||
Democratic-Republican hold |
References
[edit]- ^ "Georgia 1805 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University. Retrieved 4 December 2023.
- ^ "GA Governor". ourcampaigns.com. 18 July 2022. Retrieved 4 December 2023.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
Categories:
- 1805 Georgia (U.S. state) elections
- Georgia (U.S. state) gubernatorial elections
- 1805 United States gubernatorial elections
- November 1805 events
- 1805 in Georgia (U.S. state)
- Indirect elections
- Single-candidate elections
- 1800s in Georgia (U.S. state)
- 1800s Georgia (U.S. state) elections
- 1805 elections
- 1805 elections in North America
- 1805 elections in the United States
- United States gubernatorial elections in the 1800s
- Government of Georgia (U.S. state)